Find current given magnetic field

AI Thread Summary
To determine the current that a copper wire can carry while floating in the Earth's magnetic field, the force equation F = ILB is applied, where F is the gravitational force. The gravitational force acting on the wire is equated to the magnetic force, leading to the equation I = F/(LB). The discussion highlights confusion regarding the length of the wire needed for calculations, as the weight of the wire must be known to find the current. The wire's mass and corresponding length are critical for solving the problem accurately. Understanding these relationships is essential for determining the current in the wire.
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Homework Statement


Suppose a straight 1.90 mm diameter copper wire could just "float" horizontally in air because of the force due to the Earth's magnetic field [PLAIN]http://www.webassign.net/images/boldB.gif, which is horizontal, perpendicular to the wire, and of magnitude 4 ✕ 10-5 T. What current would the wire carry?

Homework Equations


F = ILB

The Attempt at a Solution


It seems like a simple question but the phrasing is a bit confusing and I'm having trouble visualizing it. So the F vector is pointing up in the k-direction because it's pushing the wire up, right? The B vector is horizontal so let's say in the i-direction, but how is it perpendicular to the wire if the wire is also floating horizontally?

So far, all I could do is rearrange the force equation to
I=F/LB
 
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Also, I believe F should be equal to Fg since the wire is floating in the air.

Ah, also I think B should be going into the page?
 
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So update:

I = 9.8N/ L*(4x10^-5 T)

How am I supposed to get L?
 
ooohffff said:
So update:

I = 9.8N/ L*(4x10^-5 T)

How am I supposed to get L?
Where did you get 9.8N from? You're implying (whether you know it or not) that your wire has mass of 1 kg. So what's the length of 1 kg of Cu wire with diameter 1.9mm?[/QUOTE]
 
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