Find delta from a particular epsilon

[la_med12]

I'm learning how to find delta from a particular epsilon. I'm not understanding a step in the solution for the problem listed below:

Here's the problem:
lim(x→3)x^2=9

Solution:
|x^2-9|<.05
-.05<x^2-9<.05
2.9916..<x<3.0083
2.9916..-3<x-3<3.0083..-3
-.0083..<x-3<.0083..
delta=.0083

I don't understand how:
8.95<x^2<9.05
calculates to:
2.9916..<x<3.0083..
Could someone please explain this to me.. in simple terms. Cheers!

 

[Mark44]

Take the square root of each member.

 

[la_med12]

Ah.. I guess I was looking at it for so long that I overlooked the obvious. Thanks for the help!