I'm learning how to find delta from a particular epsilon. I'm not understanding a step in the solution for the problem listed below:(adsbygoogle = window.adsbygoogle || []).push({});

Here's the problem:

lim(x→3)x^2=9

Solution:

|x^2-9|<.05

-.05<x^2-9<.05

2.9916..<x<3.0083

2.9916..-3<x-3<3.0083..-3

-.0083..<x-3<.0083..

delta=.0083

I don't understand how:

8.95<x^2<9.05

calculates to:

2.9916..<x<3.0083..

Could someone please explain this to me.. in simple terms. Cheers!

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# Homework Help: Find delta from a particular epsilon

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