Find Derivative of 3/x+2 using f(x+h) - (fx) / h

  • Thread starter Thread starter pooker
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary

Homework Help Overview

The discussion revolves around finding the derivative of the function f(x) = 3/(x+2) using the limit definition of the derivative. The specific value of x=8 is mentioned, prompting questions about its role in the derivative calculation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of substituting x=8 into the derivative after its calculation and explore the definition of the derivative at a specific point.

Discussion Status

There is a mix of agreement and disagreement regarding the interpretation of the problem. Some participants clarify the expectation to use the limit definition of the derivative at x=8, while others confirm the need for substitution after finding the derivative.

Contextual Notes

Participants are navigating the requirements set by their teacher for finding derivatives, specifically using the limit definition, and addressing any initial misunderstandings about the problem setup.

pooker
Messages
15
Reaction score
0
Our teacher wants us to find derivatives the long way

f(x+h) - (fx) / h

So anyways, on one of my questions 3 / x + 2 , x=8

I know how to find the derivative of 3 / x+2 , but why was their an x=8 next to it? Am I supposed to plug this in after finding the derivative?
 
Physics news on Phys.org
yes, you need to plug it in for x after you find the derivative.
 
I disagree with mathstudent88. The basic definition of 'derivative' is 'derivative at a given point'. From what you say, I imagine your teacher is expecting you to put it directly into the definition of the derivative of f at x0:
[tex]\lim_{h\rightarrow 0} \frac{f(x_0+ h)- f(x_0)}{h}[/tex]
which, for f(x)= 3/(x+2), at x0= 8 is
[tex]\lim_{h\rightarrow 0}\frac{3/((8+h)+2)- 3/(8+2)}{h}[/tex]
[tex]= \lim_{h\rightarrow 0}\frac{3/(10+h)- 3/10}{h}[/tex]
 
Last edited by a moderator:
With the obvious substitution of x=8 instead of x=2
 
Thanks, OfficeShredder, I've edited that mistake. (So, now I can pretend I never made it!)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
16
Views
2K