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mknut389
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I got an answer for this, but it just doesn't seem correct. Maybe someone could tell me what I am doing wrong, or that I am just over thinking the problem and I am right.
Write an expression for the differential length vector dl at the point (1,2,8) on the straight line y=2x, z=4y, and having the projection dx on the x-axis
dl=dxax+dyay+dzaz
y=2x, z=4y, therefore z=8x
therefore
dxax+2dxay+8dxaz.
since there are no variables remaining after you take the derivative, dl is then
1ax+2ay+8az
Any help would be amazing, and please excuse me if I am just being a complete idiot.
Thanks
Homework Statement
Write an expression for the differential length vector dl at the point (1,2,8) on the straight line y=2x, z=4y, and having the projection dx on the x-axis
Homework Equations
dl=dxax+dyay+dzaz
The Attempt at a Solution
y=2x, z=4y, therefore z=8x
therefore
dxax+2dxay+8dxaz.
since there are no variables remaining after you take the derivative, dl is then
1ax+2ay+8az
Any help would be amazing, and please excuse me if I am just being a complete idiot.
Thanks