Find electric Field at a point A

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FJay
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Moved from a technical forum, so homework template missing
Diagram of x-y axes with point charge Q1 at x = 0.30 m on the x-axis, charge Q2 at y = 0.60 m on the y-axis, and point A at (0.30, 0.60) forming a rectangle with the origin O.


Hi Guys,
I've been learning electric field, and i want to ask about this question.EF net = EF1 + EF2

my EF1 = 9 x 109 * 4 x 10-8 / (0.6)2 = 1 x 103 (From Q1)
EF2 = 9 x 109 * 2 x 10-8 / (0.3)2 = 2 x 103 (From Q2)

then EFnet = (2+1) x 103 = 3 x 103

and what i get from key answer is 2.2 x 103

and anyone can tell me what i miss ?
 
DrClaude said:
The electric field is a vector quantity. What is its (vector) value at A?

Diagram of a coordinate plane with point A at (0.30, 0.60). Charge Q1 sits on the x-axis at 0.30 and charge Q2 on the y-axis at 0.60. Vectors E1 point up from Q1 to A and E2 points left from A, with resultant E_NET drawn pointing up-left.


Enet = (E12 + E22)1/2

Enet = 2.23 x 103

do you mean like that bro ? anything wrong from my answer ?

then for another question like this( at different point), just do this step ?
 
FJay said:
Enet = (E1E22 + E22)1/2

Enet = 2.23 x 103
There is a typo in the first equation, but otherwise this is correct.

FJay said:
then for another question like this( at different point), just do this step ?
Yes. You first calculate the electric field itself, as a vector, and then calculate the magnitude of the vector to get the magnitude of the field.
 
DrClaude said:
Yes. You first calculate the electric field itself, as a vector, and then calculate the magnitude of the vector to get the magnitude of the field.
Thank you for your help.