Find ELectric field in these regions of a spherical shell

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Homework Help Overview

The discussion revolves around finding the electric field in three regions of a thick spherical shell with a charge density of k/r^2, specifically for the intervals r

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the choice of integration limits for calculating the electric field in different regions. There is discussion about the volume of the shell and how it relates to the integration process. Some participants express confusion about the fundamental properties of electric fields within and outside a uniformly charged spherical shell.

Discussion Status

The discussion is active, with participants sharing insights and clarifying concepts related to electric fields and integration ranges. Some have begun to understand the reasoning behind the integration limits, particularly in relation to capturing the mass or charge within specified boundaries. However, there is still a degree of uncertainty and a request for clearer explanations from others.

Contextual Notes

Participants are navigating the complexities of electric fields in spherical shells, including the implications of charge distribution and the fundamental results regarding fields inside and outside such shells. There is an emphasis on understanding the integration process and the assumptions that underlie it.

grandpa2390
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Homework Statement


a thick spherical shell carries charge density k/r^2 a<r<b
find E in the three regions r<a a<r<b b<r

Homework Equations


E dot da = Q/ε

The Attempt at a Solution


I can't understand why, when integrating, they choose for
ii to integrate between a and r,
iii and the between a and b for iii
 
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grandpa2390 said:

Homework Statement


a thick spherical shell carries charge density k/r^2 a<r<b
find E in the three regions r<a a<r<b b<r

Homework Equations


E dot da = Q/ε

The Attempt at a Solution


I can't understand why, when integrating, they choose for
ii to integrate between a and r,
iii and the between a and b for iii
What do you know about the field inside a uniformly charged spherical shell?
 
haruspex said:
What do you know about the field inside a uniformly charged spherical shell?
that it's uniform at the surface?
I don't know what you are asking.

what I have been able to gather is that they are integrating the volume of the shell. integral of 4 pi r^2 dr
for a<r<b the volume is from a - r
for b<r the volume is from a-b

I don't know why.
 
grandpa2390 said:
that it's uniform at the surface?
No, that there is no field produced inside a uniformly charged spherical shell. This is a fundamental result of enormous importance in these problems. The equally important result for outside the shell is that the field there is the same as if all of the charge were concentrated at the sphere's centre.
The same pair of results applies (of course) to gravitational fields from uniform spherical mass distributions.

Can you see how this explains the integration range?
 
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haruspex said:
No, that there is no field produced inside a uniformly charged spherical shell. This is a fundamental result of enormous importance in these problems. The equally important result for outside the shell is that the field there is the same as if all of the charge were concentrated at the sphere's centre.
The same pair of results applies (of course) to gravitational fields from uniform spherical mass distributions.

Can you see how this explains the integration range?

We are trying to capture all of the "mass" below our boundary.

Between A and B we want to capture all the mass from a to wherever r is.
If R is greater then B then we want all of the "mass" less then r which is from a to b

?
 
grandpa2390 said:
Between A and B we want to capture all the mass from a to wherever r is.
Hence the integration range from a to r.
grandpa2390 said:
If R is greater then B then we want all of the "mass" less then r which is from a to b
Hence the integration range from a to b.
You seem to have answered your own questions.
Please try to explain more clearly what it is that you do not understand.
 
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haruspex said:
Hence the integration range from a to r.

Hence the integration range from a to b.
You seem to have answered your own questions.
Please try to explain more clearly what it is that you do not understand.

No you answered it. Or at the very least, you slapped some sense into my brain, pointed... pushed my brain into the right direction.
I don't know. When you compared it to mass, it just made sense to me suddenly. I don't know. I was thinking it should have been integrated between the boundaries stated. integrated from a to b, and then from b to infinity. I didn't get it until your last reply :)

Then I just restated what I got from you in my own words for verification to make sure whether I had it : )

Thanks for your help!
 
grandpa2390 said:
restated what I got from you in my own words for verification
Verified.
 
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