Find electric Field at a point A

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SUMMARY

The discussion focuses on calculating the net electric field at point A using the formula EF net = EF1 + EF2. The user calculated EF1 as 1 x 103 N/C and EF2 as 2 x 103 N/C, leading to an initial net electric field of 3 x 103 N/C. However, the correct net electric field, accounting for vector addition, is 2.23 x 103 N/C. The participants emphasize the importance of treating electric fields as vector quantities and calculating their magnitudes accordingly.

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FJay
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Moved from a technical forum, so homework template missing
EF_zpstnbig8yt.png


Hi Guys,
I've been learning electric field, and i want to ask about this question.EF net = EF1 + EF2

my EF1 = 9 x 109 * 4 x 10-8 / (0.6)2 = 1 x 103 (From Q1)
EF2 = 9 x 109 * 2 x 10-8 / (0.3)2 = 2 x 103 (From Q2)

then EFnet = (2+1) x 103 = 3 x 103

and what i get from key answer is 2.2 x 103

and anyone can tell me what i miss ?
 
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The electric field is a vector quantity. What is its (vector) value at A?
 
DrClaude said:
The electric field is a vector quantity. What is its (vector) value at A?

EF1_zpsjbw15xo9.png


Enet = (E12 + E22)1/2

Enet = 2.23 x 103

do you mean like that bro ? anything wrong from my answer ?

then for another question like this( at different point), just do this step ?
 
FJay said:
Enet = (E1E22 + E22)1/2

Enet = 2.23 x 103
There is a typo in the first equation, but otherwise this is correct.

FJay said:
then for another question like this( at different point), just do this step ?
Yes. You first calculate the electric field itself, as a vector, and then calculate the magnitude of the vector to get the magnitude of the field.
 
DrClaude said:
Yes. You first calculate the electric field itself, as a vector, and then calculate the magnitude of the vector to get the magnitude of the field.
Thank you for your help.
 

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