Find electron's acceleration and final velocity

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SUMMARY

The discussion focuses on calculating the acceleration and final velocity of an electron in a cathode-ray tube. The electron, with a mass of 9.1 x 10-31 kg, experiences a net electrical force of 5.6 x 10-15 N over a distance of 4.0 mm, resulting in an acceleration of 6.15 x 1015 m/s2. To find the final velocity without knowing the time, the equation (v2)2 = (v1)2 + 2ad is utilized, where v1 is the initial velocity, which is zero in this case.

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  • Understanding of Newton's second law of motion
  • Familiarity with kinematic equations
  • Basic knowledge of kinetic energy and work-energy principle
  • Concept of electric force and its effect on charged particles
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An electron has a mass of 9.1*10^-31 kg. Between the electrodes of a cathode-ray tube, it moves a distance of 4.0mm, accelerated by a net electrical force of 5.6*10^-15 N. Assuming it started by rest, find it's acceleration and final velocity.

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance don't help at all if I don't know average velocity...
 
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u have accel, v1, and distance
use (v2)^2= (v1)^2 + 2ad
 
404 said:
An electron has a mass of 9.1*10^-31 kg. Between the electrodes of a cathode-ray tube, it moves a distance of 4.0mm, accelerated by a net electrical force of 5.6*10^-15 N. Assuming it started by rest, find it's acceleration and final velocity.

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance don't help at all if I don't know average velocity...

Force times distance in the direction of the force is work, and that equals change in kinetic energy.

Edit
OOPs.. two suggestions flying at the same time. They both lead to the same conclusion.
 
Ok I see, thanks.
 

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