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## Homework Statement

Find an equation for the plane that is perpendicular to the line x = 3t -5, y = 7 - 2t, z = 8 - t, and that passes through the point (1, -1, 2).

## Homework Equations

Equation of a plane: Ax + By + Cz = D

D = Ax

_{o}+ By

_{0}+ Cz

_{0}

## The Attempt at a Solution

I am not sure how to get the line x, y and z into the vector form <A,B,C>

thinking...

1 = 3t - 5....t = 2

-1 = 7 - 2t...t = 4

2 = 8 - t...t = 6

But using that in the equation of a plane does not seem to work. A little confused :(

Answer is : 3x - 2y - z = 3