Find Explicit Expression for f^-1(x) in f(x)=\frac{-2x}{3x-4}

[needhelp83]

For the function f given by the equation f(x)=$$\frac{-2x}{3x-4}$$, determine where the relation f^-1 is a function. If f^-1 is a function, write an explicit expression for f^-1(x).

Need help writing explicit expression. Any guidance?

 

[physixguru]

You have to check if the given function is invertible or not.If it is one-one and onto then it is invertible and f^-1 is a function or it exists.
I don't get you , when you say 'explicit function'.You mean the inverse?

 

[HallsofIvy]

You first say "determine where the relation f^-1 is a function" which implies that f^-1 is a function for some values of x, not others. But then you say "If f^-1 is a function". Are you sure it wasn't "determine whether the relation f^-1 is a function?

Let $y= \frac{-2x}{3x-4}$ and "swap" x and y:
[tex]x= \frac{-2y}{3y-4}[/itex]<br /> Now can you solve that for y? If so, f^-1 exists and you have found it.[/tex]