Find Explicit Expression for f^-1(x) in f(x)=\frac{-2x}{3x-4}

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SUMMARY

The discussion focuses on finding the explicit inverse function for f(x) = \frac{-2x}{3x-4}. To determine if f^-1 is a function, it is essential to verify that f is both one-to-one and onto. The process involves swapping x and y in the equation and solving for y, which confirms the existence of f^-1 if a solution is found. The explicit expression for f^-1 can be derived through algebraic manipulation of the original function.

PREREQUISITES
  • Understanding of function invertibility
  • Knowledge of algebraic manipulation
  • Familiarity with the concept of one-to-one and onto functions
  • Ability to solve equations involving rational functions
NEXT STEPS
  • Learn how to determine the invertibility of functions
  • Study the process of finding inverse functions for rational expressions
  • Explore the implications of one-to-one and onto properties in function theory
  • Practice solving for y in equations where x and y are interchanged
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Mathematics students, educators, and anyone interested in understanding function inverses and their properties, particularly in the context of rational functions.

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For the function f given by the equation f(x)=[tex]\frac{-2x}{3x-4}[/tex], determine where the relation f^-1 is a function. If f^-1 is a function, write an explicit expression for f^-1(x).

Need help writing explicit expression. Any guidance?
 
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You have to check if the given function is invertible or not.If it is one-one and onto then it is invertible and f^-1 is a function or it exists.
I don't get you , when you say 'explicit function'.You mean the inverse?
 
You first say "determine where the relation f-1 is a function" which implies that f-1 is a function for some values of x, not others. But then you say "If f-1 is a function". Are you sure it wasn't "determine whether the relation f-1 is a function?

Let [itex]y= \frac{-2x}{3x-4}[/itex] and "swap" x and y:
[tex]x= \frac{-2y}{3y-4}[/itex]<br /> Now can you solve that for y? If so, f<sup>-1</sup> exists and you have found it.[/tex]
 

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