1. The problem statement, all variables and given/known data The uniform 14-ft pole weighs 150 lbs and is supported as shown. Calculate the force P required to move the pole if the coefficient of static friction for each contact location is 0.40. (Sorry for the sideways images!) 2. Relevant equations 1.) Fmax = μs*N 2.) ∑M = 0 3.) ∑Fx = 0 4.) ∑Fy = 0 3. The attempt at a solution Step 1 I began by setting up a FBD (shown below). At points A and B I have a Normal force N and friction force F. I placed the weight vector (150 lbs) in the middle of the 14 ft beam (so 7 ft). I calculated the angle closest to point B in order to find the x-direction distance to the weight vector (which I found to be 5.6 ft). Step 2 Next I took the moment at point B, which gave me (-8)(NA) + (-5.6)(-150) - (6)(FA) = 0. Based on equation #1 I assumed FA = (.40)(NA), so I used that to find NA = 80.769 lbs Step 3 Using ∑Fy = 0, I found NA + NB - 150 = 0 to find NB = 69.230 lbs Step 4 ∑Fx = 0: ⇒ FA + FB - P = 0, which I found P = 60. My book says the answer is 118.5 lbs, so I know I'm way off, but I'm not sure where exactly. I'm thinking I'm off somewhere in my FBD, but could be elsewhere too.