Find formula for f[x] whose expansion in powers of x is

  • Thread starter Thread starter eclayj
  • Start date Start date
  • Tags Tags
    Expansion Formula
Click For Summary
SUMMARY

The discussion focuses on finding the formula for the function f[x] whose power series expansion is x + 2²x² + 3²x³ + 4²x⁴ + ... + k²xᵏ. The user identifies that this series is related to the generating function x/(1-x) and notes that differentiating the function x/(1-x)² yields the series kxᵏ. The challenge lies in manipulating these known functions to derive the desired k²xᵏ expansion. The user acknowledges the need for practice in recognizing how differentiation can lead to the correct formula.

PREREQUISITES
  • Understanding of power series expansions
  • Familiarity with generating functions
  • Knowledge of differentiation techniques
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of generating functions for polynomial sequences
  • Learn about the properties of power series and their convergence
  • Explore the relationship between differentiation and series manipulation
  • Investigate advanced techniques in combinatorial mathematics
USEFUL FOR

Mathematicians, students studying combinatorial series, and anyone interested in generating functions and their applications in series expansions.

eclayj
Messages
20
Reaction score
0
I am trying to find formula for f[x] whose expansion in powers of x is:
x + 2^2 x^2 + 3^2 x^3 + 4^2 x^4 + ... + k^2 x^k + ...

I know that this is a variation on x/(1-x). I also know that x/(1-x)^2 yields expansion in power of x = kx^k. I cannot figure out the manipulation which would give the expansion k^2x^k.

Any help is appreciated
 
Physics news on Phys.org
eclayj said:
I am trying to find formula for f[x] whose expansion in powers of x is:
x + 2^2 x^2 + 3^2 x^3 + 4^2 x^4 + ... + k^2 x^k + ...

I know that this is a variation on x/(1-x). I also know that x/(1-x)^2 yields expansion in power of x = kx^k. I cannot figure out the manipulation which would give the expansion k^2x^k.

Any help is appreciated

Well, if I had a series expansion that gave me terms kxk and I differentiated it that would give k2xk-1 and if I multiplied by x ...
 
Thank you very much. I need more practice and hopefully I will get better at seeing where a formula can be differentiated to get you close.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
845
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K