1. The problem statement, all variables and given/known data "A rod of mass 4.0 kg and length 1.5 m hangs from a hinge. The end of the rod is then given a 'kick' so that it is moving at a speed of 5 m/s. How high will the rod swing? Express you answer in terms of the angle the rod makes with the vertical. 2. Relevant equations KE(rot) = 0.5Iw2 I(rod, pivot at end) = (1/3)mL2 w = v/r h = L-Lcosθ 3. The attempt at a solution I have tried many, all yielding the incorrect answer. Posted solutions (answers only, no work shown) says that θ=64° KEo = PEf 0.5mv2 = mgh 0.5mv2 = mg(L-Lcosθ) This yields an answer of 81.39° If I do: 0.5mv2 + 0.5Iw2 = mgh " + " = mg(L-Lcosθ) this also results in an incorrect answer. I don't remember what it was. If: 0.5Iw2 = mgh → (mg(L-Lcosθ)) This one gives me θ=44.23° I've spent 9 hours on 10 homework problems, and have 3 finished. Please help me.