Find if a function is the Laplace transform of a periodic function

Click For Summary
The discussion revolves around whether the function F(s) = 1/(s(1 - e^(-s))) can be the Laplace transform of a periodic function. The initial analysis suggests that if it were, the Laplace transform of the first wave would be 1/s, leading to the conclusion that the corresponding function is a staircase function, which is not periodic. Participants express uncertainty about the criteria that F(s) must meet to confirm it as a Laplace transform of a periodic function. The consensus leans towards the idea that since the inverse Laplace transform of 1/s is H(t), which is not periodic, F(s) cannot represent a periodic function. The conversation highlights the importance of understanding the properties of Laplace transforms in relation to periodicity.
libelec
Messages
173
Reaction score
0

Homework Statement



Could \[F(s) = \frac{1}{{s(1 - {e^{ - s}})}}\] be the Laplace transform of some periodic function? Why? If so, find that periodic function

The Attempt at a Solution



If it was the Laplace transform of some periodic function, the the Laplace transform of the first wave should be 1/s, and the period T should be 1. The function whose Laplace transform is 1/s is H(t). Then the periodic function should be the stairs function, \[f(t) = \left\{ \begin{array}{l}<br /> n,x \in [nT,(n + 1)T] \\ <br /> n + 1,x \in [(n + 1)T,(n + 2)T] \\ <br /> \end{array} \right.,n \in N + \left\{ 0 \right\}\]

Now, the stairs function is of exponential order, since it's smaller or equal than the function t+1 for all t, and that is an exponential order function. Then it has a Laplace transform.

So far, so good. If the stairs function transforms to F(s) there, then F(s) is the Laplace transform of some periodic function.

But I don't think that's what the exercise asks me to do, since a latter question asks me to find the periodic function. I think there's something I have to prove through F(s) that allows me to say that it is the Laplace transform of a periodic function.

But I don't know what is that.

Any ideas?
 
Physics news on Phys.org
I'm thinking the answer is no and you should be thinking about the "why" rather than trying to find a periodic function. Your stairs function certainly isn't periodic...
 
Allright, it's true.

But then why couldn't it be periodic? Is it because the inverse Laplace transform of 1/s is H(t), and that isn't a periodic function? What does F(s) has to have to check if it belongs to a periodic function or not?
 
libelec said:
Allright, it's true.

But then why couldn't it be periodic? Is it because the inverse Laplace transform of 1/s is H(t), and that isn't a periodic function? What does F(s) has to have to check if it belongs to a periodic function or not?

Well, I didn't check your steps, but I assume you have the correct inverse with your staircase function. It isn't periodic and the FT is a 1-1 transform so doesn't that settle it?
 
Yes, but I thought there was another argument to say that. I mean, since the question seems to be theorical.
 
Anybody?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
9
Views
2K