Find inverse for f(x)= x/(1+x)

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The discussion focuses on finding the inverse of the function f(x) = x/(1+x) and demonstrating that it is one-to-one. The correct inverse function is identified as y = x/(1-x), but participants express confusion over the steps to derive it. Key attempts include manipulating the equation by switching variables and isolating x, though some participants struggle with the algebra involved. Ultimately, one user successfully solves the problem after several exchanges, indicating that the inverse can be found through systematic algebraic manipulation. The thread highlights the challenges of solving for inverses in rational functions.
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Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y

y+y=x/x
 
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jimjames said:

Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y
Start with ##y = \frac x {1 + x}##
What's the first thing you need to do?
jimjames said:
y+y=x/x
I'm not sure what you did here.
 
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)

x=y/(1+y)
y=x+xy

And now I'm stuck
 
jimjames said:
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)
The above doesn't help you with this problem. All you're doing is manipulating symbols.
jimjames said:
x=y/(1+y)
In the line above, all you did was switch x and y.
jimjames said:
y=x+xy
How did you get the equation above?
jimjames said:
And now I'm stuck
Start with y = ##\frac x {1 + x}##

For this problem DO NOT switch the variables x and y.
DO solve for x in the equation just above. In other words, x should appear only on one side of the equation.
 
y(1+x)=x
1+x=x/y
 
Last edited:
jimjames said:
y(1+x)=x
1+x=x/y
OK.

Now divide both sides by x.
 
jimjames said:
Where did you get y = x/(1+x) ?
That's the function you're trying to find the inverse of.
Multiplying both sides of this equation by 1 + x gives you the equation just below.
jimjames said:
y(1+x)=x
1+x=x/y
SammyS said:
OK.

Now divide both sides by x.
It's probably simpler to expand y(1 + x), get all terms that involve x on one side, and then isolate x.
 
jimjames said:

Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y

y+y=x/x

Why do you call this a "transcendental function"? It is just about as far from transcendental as you can get.
 
Ray Vickson said:
Why do you call this a "transcendental function"? It is just about as far from transcendental as you can get.
I changed the title a while ago for that very reason.
 
  • #10
jimjames said:
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)

x=y/(1+y)
y=x+xy

And now I'm stuck
Subtract xy from both sides: y- xy= y(1-x)= x
 
  • #11
Managed to solve this late yesterday.
Thanks for trying to help.:smile:
 
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