Find k such that the line is tangent to the graph

kdinser
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I'm not sure what they are looking for here.

Find k such that the line is tangent to the graph of the funtion

Function: x^2-kx Line: 4x-9

Just need a little push in the right direction.
 
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Hints:
You must find 2 features:
a) A point in common between the graphs of your function and your line.
b) That the slope of the function at that point equals the line's slope

This is a system of two equations!
Solutions to this system is what you are looking after (a k-value will be one of the numbers in a given solution, a x-value of the point of intersection will be the other number)
 
thanks, I'll give it a shot.
 
A solution that doesn't involve calculus: if the line is supposed to tangent the other function, then the equation 4x - 9 = x^2 - kx may only have one solution. If you solve this for x, what can you say about the discriminant?
 
arildno, did you see your mistake (in the deleted post), or did you remove it in order to not rouse my anger? :wink:
 
That's why I deleted my dumb message..
 
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