- #1
naspek
- 181
- 0
Find the following limit using L'Hospital rule..
lim...(e^x) / [(e^x) + 7x]
x->infinity
= f'(x) / g'(x)
=e^x / (e^x) + 7
= infinity/infinity
=0
am i got it right?
lim...(e^x) / [(e^x) + 7x]
x->infinity
= f'(x) / g'(x)
=e^x / (e^x) + 7
= infinity/infinity
=0
am i got it right?