- #1

PsychonautQQ

- 784

- 10

**1. The problem estatement, all variables and given/known data**

Find the Linear equation of a plane passing through the origin and points (6,2,2) and (5,-1,1)

## Homework Equations

Linear equation of a plane takes the form ax+by+cz+d = 0

## The Attempt at a Solution

So I believe I can find the direction numbers a,b,c by taking the first position minus the second position.

a = 6 - 5 = 1

b = 2 - -1 = 3

c = 2 - 1 = 2

I don't know what to do from here though. I could plug in one of the locations into the formula of format

a(x-xI) + b(y-yi) + c(z-zi) = 0

say I plug in the first position (6,2,2)

1(x-6) + 3(y-2) + 2(z-2) = 0

to get x+3y+2z-16=0

but my I'm typing that into the answer box and it's saying I'm wrong