- #1
Albert1
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$x,y\in R$
$if: \sqrt {3x+5y-2-m}+\sqrt {2x+3y-m}=\sqrt {x-200+y}\,\times\sqrt {200-x-y}$
$find:\,m=?$
$if: \sqrt {3x+5y-2-m}+\sqrt {2x+3y-m}=\sqrt {x-200+y}\,\times\sqrt {200-x-y}$
$find:\,m=?$
Albert said:$x,y\in R$
$if: \sqrt {3x+5y-2-m}+\sqrt {2x+3y-m}=\sqrt {x-200+y}\,\times\sqrt {200-x-y}$
$find:\,m=?$
Real numbers are numbers that can be found on a number line and include all rational and irrational numbers. They are often denoted by the symbol R.
This notation means that both x and y are elements of the set of real numbers. In other words, x and y are both real numbers.
To find the value of m, you would need more information about the equation. If the equation is in the form of $mx + b = y$, then you can solve for m by rearranging the equation to isolate m on one side.
Yes, m can be any real number, including negative numbers, unless there are additional constraints specified in the problem.
It is possible for there to be more than one solution for m, depending on the given equation and any constraints. For example, if the equation is in the form of $mx + b = y$, there are infinite solutions for m since any real number can be multiplied by x to equal y.