Find Magnitude & Direction for acceleration:

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SUMMARY

The problem involves calculating the acceleration of block A relative to block B, where block B has an acceleration of 4 m/s². The relative acceleration of block A with respect to block B is also 4 m/s². The correct approach to find the magnitude of acceleration for block A is to use vector addition, resulting in a total acceleration of 8 m/s². The components of this acceleration are calculated as 7.52 m/s² in the x-direction and 2.74 m/s² in the y-direction, leading to a direction of approximately 20.02 degrees.

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ladkee
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Homework Statement

:
Block B has acceleration of 4 m/s2... Relative acceleration of block A w/ respect to B is 4 m/s2. Find magnitude & direction of accel for A?[/B]

Homework Equations



a_A = a_B + a_A/B[/B]

The Attempt at a Solution



a_A = 4 +4 = 8 m/s2 <--

8*cos(20) = 7.52 (x-component)

8*sin(20) = 2.74 (y-component)

direction= inverse tangent of (2.74 / 7.52) = 20.02 degrees <--

this was my attempt, not sure if I did it correctly. [/B]
 

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ladkee said:
a_A = a_B + a_A/B
Those are vectors, you cannot add their magnitudes.
 

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