Find Matrix B for Complex Number T(z)

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Homework Help Overview

The problem involves finding the matrix representation of a linear transformation T defined on complex numbers, specifically T(z) = w · z, where w is a complex number. The context is within the framework of vector spaces over the reals, using the basis {1, i} for complex numbers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the concept of finding the matrix representation of the transformation T and question the terminology used, particularly regarding the "standard basis of T." There is an exploration of how to compute T(1) and T(i) to derive the matrix representation.

Discussion Status

Some participants have provided guidance on how to approach the problem by suggesting the calculation of T(1) and T(i) as a means to find the matrix. There appears to be a productive exchange of ideas, with some participants expressing confusion and seeking clarification on the terminology and steps involved.

Contextual Notes

There is a sense of urgency among participants due to an upcoming exam, which may influence the depth of the discussion. Some participants express confusion about the definitions and concepts related to the transformation and its matrix representation.

gothloli
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Homework Statement


Let w = a + bi be a complex number and let T : C -> C be defined by T(z) = w · z.
Considering C as a vector space over R, find the matrix B representing T relative to
the basis {1, i} of C.


Homework Equations





The Attempt at a Solution


I think you use eigenvalues and eigenvectors, if T is diagonalizable, but my main problem is finding standard basis of T since z is not defined, hence can you guide me there thanks, please help I have an exam tomorrow!.
 
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gothloli said:

Homework Statement


Let w = a + bi be a complex number and let T : C -> C be defined by T(z) = w · z.
Considering C as a vector space over R, find the matrix B representing T relative to
the basis {1, i} of C.


Homework Equations





The Attempt at a Solution


I think you use eigenvalues and eigenvectors, if T is diagonalizable
I don't see that eigenvalues or eigenvectors enter into this at all.
gothloli said:
, but my main problem is finding standard basis of T
"standard basis of T" makes no sense to me. A basis is associated with a vector space, not a transformation.

You are given a basis for C; namely {1, i}. What is T(1)? What is T(i)?
gothloli said:
since z is not defined, hence can you guide me there thanks, please help I have an exam tomorrow!.
 


sorry I meant to say standard matrix of T not basis. Then can you tell me how to solve the question please, I have an exam tomorrow, I'm so confused, I just need help.
 


gothloli said:
sorry I meant to say standard matrix of T not basis. Then can you tell me how to solve the question please, I have an exam tomorrow, I'm so confused, I just need help.

w=a+bi. As Mark44 suggested, if you find T(1) and T(i) then those will be the column vectors of the 2x2 matrix for T in the basis {1,i}. What are they? Express them in terms of the basis.
 


Dick said:
w=a+bi. As Mark44 suggested, if you find T(1) and T(i) then those will be the column vectors of the 2x2 matrix for T in the basis {1,i}. What are they? Express them in terms of the basis.

okay so I get (a -b)
(b a)

thanks for the help, you made it clear for me.
 


Dick said:
w=a+bi. As Mark44 suggested, if you find T(1) and T(i) then those will be the column vectors of the 2x2 matrix for T in the basis {1,i}. What are they? Express them in terms of the basis.

I get the matrix (a -b)
(b a)
I don't have time to find the matrix input on this thing.

Thanks for the help, you made it clear
 


gothloli said:
I get the matrix (a -b)
(b a)
I don't have time to find the matrix input on this thing.

Thanks for the help, you made it clear

I'm clear you've got it. That's what's important. Don't worry about the notation. I fudge it a lot myself. I'd express that as [[a,-b],[b,a]] and just hope people get it.
 

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