Find max distance box on hingedbeam can be before rope snaps

[isukatphysics69]

Homework Statement

Homework Equations

torque = force * distance

The Attempt at a Solution

Torque forces :
T_{ForceTensionRopeY} - T_BOX - T_BEAM = 0

Net forces Y:
∑F_Y = F_TensionRopeY + F_HingeY - W_BEAM - W_BOX = 0

Net forces X:
∑F_X = F_HingeX - F_TensionRopeX = 0

This is my first torque problem so i want to make sure that i have all of my forces properly, i have been spinning wheels here for 30 minutes unable to solve. I will continue trying but want to see if i have all of the forces correctly

 

[ehild]

Homework Statement

View attachment 225177

Homework Equations

torque = force * distance

The Attempt at a Solution

Torque forces :
T_{ForceTensionRopeY} - T_BOX - T_BEAM = 0

Net forces Y:
∑F_Y = F_TensionRopeY + F_HingeY - W_BEAM - W_BOX = 0

Net forces X:
∑F_X = F_HingeX - F_TensionRopeX = 0

This is my first torque problem so i want to make sure that i have all of my forces properly, i have been spinning wheels here for 30 minutes unable to solve. I will continue trying but want to see if i have all of the forces correctly

You need the torque equation only. Write the torques with respect to the hinge. Take the tension equal to the maximum value.

 

[isukatphysics69]

You need the torque equation only. Write the torques with respect to the hinge. Take the tension equal to the maximum value.

I believe i need the y component only of the tension tho

525 = 1.325*182 +x*225
525 - 241.15 = x*225
283.85/225 = 1.26m = x was incorrect

That is why i had the other equations so that i can find that y component of the tension​

i believe i can actually just find that y component easily 1 sec

​

 

[ehild]

I believe i need the y component only of the tension tho

525 = 1.325*182 +x*225
525 - 241.15 = x*225
283.85/225 = 1.26m = x was incorrect

That is why i had the other equations so that i can find that y component of the tension​

i believe i can actually just find that y component easily 1 sec

How is the torque defined? What is the torque of the tension?
You have the angle between the rope and the bar (30 °).

 

[isukatphysics69]

How is the torque defined?
You have the angle between the rope and the bar (30 °).

I have defined the torque as negative downwards and positive upwards
torque is force*distance

So i see what youre saying here i think, 525sin(30)*2.65
this would be the maximum force in the y direction multiplied by the distance. This is the torque of the rope

 

[ehild]

I have defined the torque as negative downwards and positive upwards
torque is force*distance

So i see what youre saying here i think, 525sin(30)*2.65
this would be the maximum force in the y direction multiplied by the distance. This is the torque of the rope

Yes. So what did you get for x?

 

[isukatphysics69]

Yes. So what did you get for x?

2.019 meters thank you!

 

[ehild]

2.019 meters thank you!

You are welcome.