smillphysics
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A 0.90 kg mass on a spring oscillates horizontally with little friction according to the following equation: x = 0.090cos(2.90t), where x is in meters and t in seconds. Find the maximum energy stored in the spring during an oscillation.
X=a*cos (omega*t)
omega =2pi*frequency = sqrot k/m
x=mg/k which came from kx=mg
I got k=7.569 from omega=sqrt m/k, then I plugged k into kx=mg and got x=1.165
from here I would like to use well...im unsure. is the total energy equal to 1/2kx^2 because I have x and k if they are correct.
X=a*cos (omega*t)
omega =2pi*frequency = sqrot k/m
x=mg/k which came from kx=mg
I got k=7.569 from omega=sqrt m/k, then I plugged k into kx=mg and got x=1.165
from here I would like to use well...im unsure. is the total energy equal to 1/2kx^2 because I have x and k if they are correct.