Find Moment Around A with 3D Vectors: B & C

  • Thread starter Thread starter LeftBrain
  • Start date Start date
  • Tags Tags
    3d Moment
AI Thread Summary
The discussion focuses on calculating the moment around point A using 3D vectors B and C, with a force magnitude of 1919N. The user attempts to find the correct r-vector for calculating the moment but is confused about which arm to use and whether their calculations are correct. They initially calculate the unit vector and force components but are advised to use the r-vector connecting point A to the force application point. The importance of using the correct r-vector and understanding the relationship between force and distance for calculating the moment is emphasized. The user seeks clarification on the proper approach to complete their homework assignment.
LeftBrain
Messages
3
Reaction score
0

Homework Statement


wbqf13.jpg


A (0,0,0)
B(5,6,1)
C(3,0,4)

|F|= 1919N

Homework Equations

The Attempt at a Solution



Cartesian:
B= {5i + 6j + 1k}
C= {3i + 4k}

rCB ={2i + 6j - 3k}

|rCB| = sqrt(22 + 62 + 32) = 7

Unit vector = rCB / |rCB| = {2/7i + 6/7j - 3/7k}

F = |F| * Unit vector = 1919 {2/7i + 6/7j - 3/7k} = 548.29i + 1644.86j - 822.43k

Now firstly, I'm not sure if I even did the above part correctly, but to find the moment I'm a bit lost and my don't seem to have much in my notes about this...

I think the next step is using cross product, but I'm a bit lost as to which arm to take to find moment about A...

If I use rBA I get:

MA = rBA x F = 6579.44i - 4660.44j - 4934.56k

WELP! Need help!

Cheers LB
 
Physics news on Phys.org
LeftBrain said:

Homework Statement


wbqf13.jpg


A (0,0,0)
B(5,6,1)
C(3,0,4)

|F|= 1919N

Homework Equations

The Attempt at a Solution



Cartesian:
B= {5i + 6j + 1k}
C= {3i + 4k}

rCB ={2i + 6j - 3k}

|rCB| = sqrt(22 + 62 + 32) = 7

Unit vector = rCB / |rCB| = {2/7i + 6/7j - 3/7k}

This is not the r-vector for use in calculating the moment about point A. What is the r-vector you need instead?

(Hint: What is the Force pulling on?)
F = |F| * Unit vector = 1919 {2/7i + 6/7j - 3/7k} = 548.29i + 1644.86j - 822.43k

Now firstly, I'm not sure if I even did the above part correctly, but to find the moment I'm a bit lost and my don't seem to have much in my notes about this...

You can always find discussions and examples of how to calculate the moment on the web.
I think the next step is using cross product, but I'm a bit lost as to which arm to take to find moment about A...

If I use rBA I get:

MA = rBA x F = 6579.44i - 4660.44j - 4934.56k

WELP! Need help!

Cheers LB
See above. Remember, the problem asks for the magnitude of the moment, so don't forget that!
 
So I need to use rBC instead?
 
LeftBrain said:
So I need to use rBC instead?
No, you need to use the r-vector which connects point A to the end of the rope pulling on the end of bar AB.

Remember, calculating a Moment requires a Force and some kind of Distance between the force and the axis of rotation caused by the moment.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top