Find N to Solve Summation Math Problem - Get Help Now!

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The discussion focuses on determining the value of N that satisfies the inequality \(0 < e - \sum_{n=0}^{N} \frac{1}{n!} < 10^{-14}\). The user seeks assistance in solving this mathematical problem. A key insight provided is that the difference between e and the summation can be approximated by \( \frac{1}{(N+1)!} \), leading to the conclusion that N must be sufficiently large such that \( \frac{1}{N \cdot N!} < 10^{-14} \).

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tomboi03
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Find an N so that
N​
0< e-[tex]\sum[/tex] 1/n! < 10^-14
n=0​

I seriously don't know how to go about this problem.
Please help me out.

Thanks
 
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since we know
e=1+1+1/2+1/6+...+1/n!+...
e-(1+1+1/2+1/6+...+1/n!)=1/(n+1)!+...<1/(n*n!)
so chose n at least so large that
1/(n*n!)<10^-14
 

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