Find Reactions to Overhanging Beam

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To find the reactions for an overhanging beam, ensure that both the net force and torque around a chosen point are zero for equilibrium. Select any point to calculate torques from all forces, which must sum to zero. When isolating variables like Dy, substitute them into the overall force equation to solve for other reactions. Clarification on the placement of forces and distributed loads is essential, as is understanding how to calculate the average position of forces. Drawing the problem can help visualize the forces and their locations more clearly.
Ozkan Suna
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The question is:

How do I find all the reactions? I haven't worked with a similar problem before, so I'm kinda confused. Hope someone will help!

Thanks from now.
 
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Finding all forces should be easy from the sketch. To calculate their values: Both net force overall and torque around a point of your choice have to be zero in equilibrium.
 
'' Point of my choice has to be zero '' Does it mean I have to add a charnier? Sorry for the confusion
 
You don't have to add anything. Pick a random point. Calculate all torques around that point from all the forces. The sum has to be zero.
 
So if I want the moment ΣMz = 0; Dy * 6a - P*10a - p*5a*2,5a = 0
and then isolate Dy and substitute it in ΣFy = 0; By + Dy = 5ap + P??
 
If you introduce new variables, you should define them somewhere. An explanation what is what would be useful as well.
Ozkan Suna said:
P*10a
Why 10a?
Ozkan Suna said:
- p*5a*2,5a
","? And assuming you mean 2.5, why 2.5?
Ozkan Suna said:
and then isolate Dy and substitute it in ΣFy = 0; By + Dy = 5ap + P??
Sure.
 
1) We have a single force at the end of the beam. So I say the force multiplied with the total lenght.

2) From the left side of the beam to the half we have distributed load. So I want to find where the single force attacks, and that is on the half on the beam, right?

Sorry for my bad English!
 
Ozkan Suna said:
2) From the left side of the beam to the half we have distributed load. So I want to find where the single force attacks, and that is on the half on the beam, right?
What is the middle between "2a to the left" and "3a to the right"?
 
Oh, so we have to split it up to 2a/2 = a and 3a/2 = 1.5a?
 
  • #10
You can split it in two pieces, but simply finding the middle works as well. The middle is not 2.5 a to the right of the support.
 
  • #11
1.5 a right?
 
  • #12
No.

Draw it on a piece of paper if that helps. Or use signs: Where is the middle between -2 and +3?
 
  • #13
a?
 
  • #14
Stop guessing please. How do you calculate the average between two values?
 
  • #15
Not guessing, it's confusion.
The average of -2 and 3 is: -2 + 3 / 2 = 1/2
 
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