Find S/E in Filtres & OPAMP Circuits: A Complex Schema

  • Thread starter Thread starter ace130
  • Start date Start date
  • Tags Tags
    Amp Opamp
Click For Summary

Homework Help Overview

The discussion revolves around analyzing a complex filter and operational amplifier (op-amp) circuit to find the function S/E. Participants are exploring the relationships between various impedances and voltages within the circuit.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the summation of impedances in series and parallel configurations, questioning the validity of combining Z1 and Z' due to differing currents and voltages. Some express confusion regarding voltage relationships and the implications of certain assumptions.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants providing guidance on how to combine impedances. However, there is no explicit consensus on the correct method, and multiple interpretations are being considered.

Contextual Notes

Participants mention constraints related to the circuit's configuration, such as the impact of the Vs node and the challenges of finding a stable solution without summing components. There is also a reference to the use of a voltage divider, indicating a potential area of misunderstanding.

ace130
Messages
8
Reaction score
0
So this is the circuit of a filtre and it's complex schema :

x7TeCWd.jpg

The question was find the fonction S/E .In order to find S/E , I had to sum up impedances in serie or parallel, for example R2 and Z2 have the same current so we put R2+Z2=Z', but can I sum Z1+Z' ? since they have different current and voltage,The rule says that serie means same current and parallel means same voltage .
My first attempt is to consider Z1 and Z' are in parallel but the result was weird.
I want to know if that green statement is correct , and if you wish you can give me a hint or solution the find S/E.
 

Attachments

  • x7TeCWd.jpg
    x7TeCWd.jpg
    12.1 KB · Views: 632
Physics news on Phys.org
(1) The green statement is correct.
(2) Assuming no current flows out of S, then you are correct that R2 and Z2 are in series.
(3) The correct next step is to consider Z1 and Z'=R2+Z2 in parallel. What was "weird" about this?
(4) Do you then see how to incorporate R1?
 
I'm a little confused, here is my friend attempt (E=Ve, S=Vs , Z'=Zeq1) , considering that his part 2 is correct , so the voltage at Z1(Zc1) is V1 , but the voltage at Z' is obviously V1-S

Gw5GmBG.jpg
 

Attachments

  • Gw5GmBG.jpg
    Gw5GmBG.jpg
    46.9 KB · Views: 747
ace130 said:
I'm a little confused, here is my friend attempt (E=Ve, S=Vs , Z'=Zeq1) , considering that his part 2 is correct , so the voltage at Z1(Zc1) is V1 , but the voltage at Z' is obviously V1-S

View attachment 219463
not quite.
R2 and Z2 are in series. so Zeq(1) will be R2 + Z2, note the other end of Zeq(1) has to be tied to ground.

By doing this you "lose" your Vs node. You will have to resolve for this later.

Then Zeq(1) is in parallel with Z2, the combo of which is in series with R1. You should then be able to use ohms law to find Ie = Ve / (R1 + (Zeq || Z2)). You then solve for the current through Zeq, and go from there!

note: there are other easier ways to solve this, but you likely have not learned them yet.
 
well, I knew that Vs would cause problems when adding R2 and Z2 , so I tried to find E/S without sum up any component , instead I wrote E/S= (V1/S)*(E/V1) and calculate each expression , it takes more time but the result seems to be more convenient , the problem is I can't find a "stable" solution , I don't know which method is correct
 
ace130 said:
instead I wrote E/S= (V1/S)*(E/V1)

that is not a true statement though. where did you get it?

DO you know what a voltage divider is?
 
donpacino said:
that is not a true statement though. where did you get it?

DO you know what a voltage divider is?
It is ! it's simple math ? I just inverse it , because I'm using a Right-to-left Keyboard... my bad
SGHzRVM.jpg
 

Attachments

  • SGHzRVM.jpg
    SGHzRVM.jpg
    8.9 KB · Views: 272

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
39
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K