Find Tension in Cable for 4.0m Beam w/ 1200N Weight

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The discussion centers on calculating the tension in a cable supporting a 4.0-meter beam weighing 1200 N, with a 2100 N dead weight hanging from its top. The beam is in static equilibrium, meaning the net torque is zero. The cable is oriented at 25° from the horizontal. The tension in the cable can be determined using the principles of static equilibrium and torque calculations.

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A uniform, 4.0-meter long beam weighing 1200 N is supported by a cable. The beam pivots at the bottom, and a 2100 N dead weight hangs from its top. Since the beam is not accelerating, you know that the net torque on it is zero. Find the tension in the cable, which is oriented at 25° from the horizontal i.e., perpendicular to the beam.
 
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DH214 said:
A uniform, 4.0-meter long beam weighing 1200 N is supported by a cable. The beam pivots at the bottom, and a 2100 N dead weight hangs from its top. Since the beam is not accelerating, you know that the net torque on it is zero. Find the tension in the cable, which is oriented at 25° from the horizontal i.e., perpendicular to the beam.

DH214, this is the fourth time that you have tried to get us to answer questions for you without making any attempt yourself.

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