# Find the 2nd Derivative - Basic Calc

1. Oct 8, 2009

### bobraymund

1. The problem statement, all variables and given/known data

If g is a twice differentiable function and f(x) = xg(x^2), find f" in terms of g, g', and g".

2. Relevant equations

3. The attempt at a solution

I tried this with a lot of work, wouldn't be bothered to put it all here, and came up with:

f'' = (6x)*g'(x^2) + (4x^3)*g"(x^2)

Is this right or am I completely off? This question was confusing...

Is this even what they're asking for?

-Bob

2. Oct 8, 2009

### Avodyne

Your answer is correct! Getting it involves repeated use of the chain rule and the product rule.

3. Oct 8, 2009

### bobraymund

Thanks!

I thought it looked like a weird answer so wasn't entirely sure.

Gracias,
Bob

4. Oct 8, 2009

### NastyAccident

Yup, you are correct! I got: 4*x^3*g''(x^2)+6*x*g'(x^2).

As Avodyne said, "Getting it involves repeated use of the chain rule and the product rule."

So, you've just showed that you understand both of these concepts well!

Solve in terms, generally means solve the equation/formula with y on one side and x on the other side.... So, you are making x independent of your equation/formula with y being dependent on x. IE: Think of the cartesian plane, (x,y) {(1,1), (2,2), (3,3), etc...}

Sincerely,

NastyAccident