Find the Area of the Parallelogram

AI Thread Summary
To find the area of the parallelogram defined by vertices P1, P2, P3, and P4, the vectors representing adjacent sides must be identified. The vertices are given as P1 = (1, 2, -1), P2 = (4, 2, -3), P3 = (6, -5, 2), and P4 = (9, -5, 0). A common approach is to consider P1P2 and P3P4 as potential opposite sides, requiring verification of their parallelism. The area can then be calculated using the cross product formula ||U X V||, where U and V are the vectors formed by the chosen adjacent sides. Proper identification of the vectors is crucial for accurate area calculation.
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Homework Statement


Find the area of the paralellogram with vertices P1, P2, P3, and P4. *Not all pairs of vertices will give rise to a side.

P1 = (1, 2, -1)
P2 = (4, 2, -3)
P3 = (6, -5, 2)
P4 = (9, -5, 0)

Homework Equations


||U X V || is the area of the parallelogram having U≠0 and V≠0 as adjacent sides.


The Attempt at a Solution



How do you know which set of points will create a vector that are adjacent to each other?
 
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You are told that this is a parallelogram- opposite sides must be parallel to one another.
 
And usually such problems give the points going around the object. So if it is a parallelogram and the points aren't mixed up, you might expect ##P_1P_2## and ##P_3P_4##to be opposite sides. Of course, you would have to check to see if those two sides are parallel to see if that is true...
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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