Find the average rate of flow of blood - artery

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SUMMARY

The average rate of flow of blood in an artery can be calculated using the velocity equation v=k(R^2-r^2). To find the average flow, one must integrate the velocity over the area of the artery, treating it as a cylindrical section. The correct approach involves integrating the product of the velocity and the differential area (dA = 2πr dr) and then dividing by the total cross-sectional area of the artery. The resulting average flow is expressed as 2R^2k/3, confirming the necessity of considering the two-dimensional nature of the artery's cross-section.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques
  • Familiarity with the concept of average value in mathematics
  • Knowledge of cylindrical coordinates and area calculations
  • Basic principles of fluid dynamics related to blood flow
NEXT STEPS
  • Study the application of integration in cylindrical coordinates
  • Learn about the average value of functions over two-dimensional regions
  • Explore fluid dynamics principles, particularly in biological systems
  • Investigate the mathematical modeling of blood flow in arteries
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Students studying calculus, medical professionals interested in hemodynamics, and anyone involved in mathematical modeling of biological systems will benefit from this discussion.

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Homework Statement



The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is v=k(R^2-r^2) where K is the constant of proportionality. Find the average rate of flow of blood along a radius of the artery. (use 0 and R as the limits of integration)

Homework Equations



Average value formula in a closed interval using intergration

The Attempt at a Solution



I'm having difficulty finding what variable to integrate.
I'm using the math to find the average value, I integrate the equation in terms of r with the upper limit R and a lower limit of 0. My answer does come out as a single number containing variables 2R^2k/3. I don't know if this is the right way of doing the problem.
Thanks for your help!
AJ
 
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It would help if you showed the actual integration you performed. Keep in mind that the artery is treated as a cylindrical section, so your differential areas are rings (annuli) of thickness dr and circumference 2(pi)r (that is, dA = 2(pi)r dr). You are not taking a one-dimensional average of a function, but one that is two-dimensional, so you must integrate v(r) · dA and divide that result by the cross-sectional area of the artery (integral of dA). This is because there is much more area contributing to the average farther away from the symmetry axis of the artery than there is close to that axis.
 

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