Find the Coefficient of Kinetic Friction for a 40N Case

[Mar17]

Homework Statement

a force of 15 N {south} moves a case weighing 40 N { down} across a level surface at constant velocity. what is the coefficient of kinetic friction for the cae on the counter

Homework Equations

Force of friction = the coefficient of friction(μ) x normal force

The Attempt at a Solution

Force of friction = the coefficient of friction (μ )x normal force
55N= μ x 55
=1

 

[NeoDevin]

If the case is moving at constant velocity, then the force of friction must exactly equal the applied force.

 

[Mar17]

thank you. :)