Find the constants for given IVP

  • Thread starter Thread starter Feodalherren
  • Start date Start date
  • Tags Tags
    Constants Ivp
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 1K views
Feodalherren
Messages
604
Reaction score
6

Homework Statement


Untitled.png


Homework Equations


DifEqs

The Attempt at a Solution



y ' = 4C1e-4xSinX - 4C2e-4xCosX

y'(0) = -1

-1 = 0 - 4C2

Therefore

C2 = 1/4

Not correct. What am I doing wrong?
 
Physics news on Phys.org
Sigh... obviously. Can't believe I just did that. Thanks!
 
Feodalherren said:
What am I doing wrong?
  1. [itex]y=c_{1}e^{-4x}cos(x)+c_{2}e^{-4x}sin(x)[/itex]
  2. [itex]y'=c_{1}(-4e^{-4x}cos(x)-e^{-4x}sin(x))+c_{2}(-4e^{-4x}sin(x)+e^{-4x}cos(x))[/itex]
Now insert for y(0) and y'(0) and solve.
 
  • Like
Likes   Reactions: Feodalherren
Personally, I would find it easier to write the solution as [itex]y= e^{-4x}(C_1 cos(x)+ C_2 sin(x))[/itex].

Then, by the product rule, [itex]y'= -4e^{-4x}(C_1 cos(x)+ C_2 sin(x))+ e^{-4x}(-C_1 sin(x)+ C_2 cos(x))[/itex].
 
  • Like
Likes   Reactions: Feodalherren
Yeah I got it dudes. I was just being stupid and completely forgot the product rule.

Thanks