Kelsi_Jade
- 58
- 0
Homework Statement
Homework Equations
/ 3. The Attempt at a SolutionLooking to solve mistakes to study from homework. Here's what I had so far[/B]
Find the Current Flowing through each resistor
- Thread starter Kelsi_Jade
- Start date
-
- Tags
- Current Electronics Resistor
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
9 replies · 7K views
Looking to solve mistakes to study from homework. Here's what I had so far[/B]
- 16,219
- 4,934
Good. Now: what is your question ?
magoo
- 167
- 45
The batteries are arranged in opposite polarity. Check your second equation.
Kelsi_Jade
- 58
- 0
I'm just wondering how to find the Voltage drop.
Would I need to find the voltage using V=IR for each of the currents that I found and then I could observe the drop from V1 to V2?
Would I need to find the voltage using V=IR for each of the currents that I found and then I could observe the drop from V1 to V2?
- 16,219
- 4,934
IS it clear what you mean with V1 and V2 ? What do you think of Magoo's remark ?
Kelsi_Jade
- 58
- 0
Aren't the currents going in the same direction, though? - They're both moving in a clock-wise direction?magoo said:
- 16,219
- 4,934
Yes, so do the voltage drop over the 2 k##\Omega## and the 5V have he same sign or an opposite sign ?
Kelsi_Jade
- 58
- 0
Hmm...If you start with 10V and on the opposite side is 5V, is it bc of Kirchhoff's voltage law that the voltage drop would be negative over the 2kOhm to 5V battery?
Because your overall voltage of the loop should end up =0?
Because your overall voltage of the loop should end up =0?
Gold Member
- 3,489
- 1,173
Sum of potential changes (gains and drops) should be zero.Kelsi_Jade said:
Usually, you can't predict that. You should assume the directions of currents first and solve the KVL and KCL equations. If the current direction assumed is incorrect, you'll get a minus sign in the answer.Kelsi_Jade said:
Archie Medes
- 33
- 5
A few things:
Voltage polarity is due to potential difference.
Your equations don't seem to be loop (mesh) equations.
The direction to assign a current for analysis is arbitrary, as long as you don't swap it's direction mid analysis. If you guessed the correct direction, the result will be positive. Otherwise, the result will be negative. Compare your result, to the direction you assigned, and that will tell you which way current is flowing.
Voltage polarity is due to potential difference.
Your equations don't seem to be loop (mesh) equations.
The direction to assign a current for analysis is arbitrary, as long as you don't swap it's direction mid analysis. If you guessed the correct direction, the result will be positive. Otherwise, the result will be negative. Compare your result, to the direction you assigned, and that will tell you which way current is flowing.