- #1
merced
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Find the interval on which the curve y = [tex]\int_0^{x}[/tex](1/(1 + t + t2))dt
is concave upward.
I know that I need to find the derivative of the integral.
But I can't figure out how.
I tried to use substitution, letting u = (1 + t + t 2).
Then du = (1 + 2t)dt. But that doesn't work.
is concave upward.
I know that I need to find the derivative of the integral.
But I can't figure out how.
I tried to use substitution, letting u = (1 + t + t 2).
Then du = (1 + 2t)dt. But that doesn't work.