Find the determinant of a matrix

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Homework Help Overview

The discussion revolves around finding the determinant of a 3x3 matrix, specifically the matrix A provided by the original poster. Participants are exploring different methods to calculate the determinant and confirming the correctness of the original poster's answer.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods for calculating the determinant, including a method referred to as "ninja math" and the cofactor method. There are questions about the validity of the original poster's answer and the application of properties of determinants, such as multiplicativity.

Discussion Status

Some participants have confirmed the original poster's answer, while others have provided alternative methods and insights into calculating determinants. There is an ongoing exploration of how to find the determinant of a matrix raised to a power, with some guidance offered regarding the multiplicative property of determinants.

Contextual Notes

There is mention of the original poster's lack of LaTeX formatting for the matrix and a reference to a calculator's output. The discussion includes a specific method for 3x3 matrices, known as the Sarus rule, which is noted to be applicable only for that order.

sara_87
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Bonsoir everyone

can anyone confirm if i got the answer right or wrong:

Question:

find the determinant of A. A is a matrix and is equal to

1 5 -3
3 -3 3
2 13 -7

(i think you've already guessed that i don't have latex)

My answer:

i got -18


I would be grateful if anyone could confirm my answer, and if it's wrong i'll write out all the steps that i did in order to get that answer

Merci :smile:
 
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Did you use ninja math or cofactors? I like ninja math:

[(1*-3*-7)+(5*3*2)+(3*13*-3)]-[(-3*-3*2)+(3*13*1)+(5*3*7)]=? <----- Is that -18?
 
You're correct.
 
According to my TI-83, that's it
 
Thank you all so much!...(i knew i was right ;) )

and you could help me further by telling me how to find det(B^3) where det B= 4

i don't think that it's as simple as 4^3...is it?
 
ninja math?
 
Det is multiplicative (Det(XY)=Det(X)Det(Y)). You have been taught this. So use it.
 
so it is 4^3, and my answer is 64
 
Ninja math, basketweave, whatever you want to call it. You slice along the diagonals. So if you have matrix A, you would do

(A11*A22*A33+A12*A23*A31+A21*A32*A13)-(A13*A22*A31+A12*A21*A33+A23*A32*A11)
 
  • #10
Mindscrape said:
Ninja math, basketweave, whatever you want to call it. You slice along the diagonals. So if you have matrix A, you would do

(A11*A22*A33+A12*A23*A31+A21*A32*A13)-(A13*A22*A31+A12*A21*A33+A23*A32*A11)

That 'Ninja math' method is also called the Sarus rule, and it only applies for determinants of matrices of order 3.
 
  • #11
Yes I forgot to mention it is only for 3x3. Sarus rule? I did not know that. I prefer ninja math other Sarus rule though.
 

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