Electric field vector equation: Finding the neutral point for two charges

[kuruman]

And what is the value of $x$ from that equation?

 

[tellmesomething]

Yes $$ \frac {kq} {x²}= \frac {k4q} {(√2-x)²} $$

I get x as $\frac {√2} {3}$ @kuruman

 

[tellmesomething]

And what is the value of $x$ from that equation?

Further I can multiply this with the unit vector and find the vevtor joining r2 and r3 as well as r3 and r1

 

[tellmesomething]

Further I can multiply this with the unit vector and find the vevtor joining r2 and r3 as well as r3 and r1

And from there its easy to find out the position vector r3

 

[kuruman]

And from there its easy to find out the position vector r3

Go ahead and do it.

 

[tellmesomething]

Go ahead and do it.

Done! Got the answer.