Find the eigenstates of a basis in terms of those of another basis?

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SUMMARY

This discussion focuses on expressing the eigenstates of the position operator, \(\hat{x}\), in terms of the eigenstates of the number operator, \(\hat{N}\). The number operator is defined as \(\hat{N} = \hat{a}^\dagger\hat{a}\) with eigenstates \(|n\rangle\) satisfying \(\hat{N}|n\rangle = n|n\rangle\). The position operator is represented as \(\hat{x} = \gamma(\hat{a}^\dagger + \hat{a})\), where \(\gamma = \sqrt{\frac{\hbar}{2m\omega}}\). A recurrence relation for the coefficients \(C_n\) is derived, leading to the equation \(C_{n+1} = \frac{x}{\gamma\sqrt{n+1}}C_n - \frac{\sqrt{n}}{\sqrt{n+1}}C_{n-1}\), which requires further exploration to find a closed-form solution.

PREREQUISITES
  • Understanding of quantum mechanics, specifically operators and eigenstates.
  • Familiarity with the number operator and its eigenstates.
  • Knowledge of position operator representation in quantum mechanics.
  • Ability to manipulate recurrence relations in mathematical physics.
NEXT STEPS
  • Research quantum coherent states and their relationship to the position operator.
  • Explore the derivation of position-space wavefunctions, particularly \(\langle x'|n\rangle\).
  • Study the implications of the recurrence relation for coefficients in quantum mechanics.
  • Investigate closed-form solutions for eigenstate coefficients in quantum harmonic oscillators.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying quantum harmonic oscillators and operator theory. This discussion is beneficial for anyone seeking to understand the relationship between different operator eigenstates in quantum systems.

thecommexokid
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Homework Statement



This isn't exactly a homework question, but I figured this would be the best subforum for this sort of thing. For the sake of a concrete example, let's just say my question is:

Express the position operator's eigenstates in terms of the number operator's eigenstates.

Homework Equations



The number operator is given by
\hat{N} = \hat{a}^\dagger\hat{a}.
It has eigenvalues and eigenstates
\hat{N}|n\rangle = n|n\rangle.
The position operator is given by
\hat{x} = \sqrt{\frac{\hbar}{2m\omega}}\Big(\hat{a}^\dagger+\hat{a}\Big) \equiv \gamma\Big(\hat{a}^\dagger+\hat{a}\Big).
The action of the position operator on one of the number eigenstates is
\hat{x}|n\rangle = \gamma\Big(\hat{a}^\dagger|n\rangle + \hat{a}|n\rangle\Big)<br /> =\gamma\Big(\sqrt{n+1}|n+1\rangle + \sqrt{n}|n-1\rangle\Big).

The Attempt at a Solution



We'd like to find eigenstates of \hat x, that is, states |x\rangle satisfying
\hat x|x\rangle = x|x\rangle.
The number basis is complete, so whatever these states we're looking for might be, they are representable as a linear combination of the number states:
|x\rangle = \sum_n |n\rangle\langle n|x\rangle;
I just need to know the coefficients C_n \equiv \langle n|x\rangle.

If I look again at the action of \hat x,
\hat x|x\rangle = \sum_n \hat x|n\rangle\langle n|x\rangle \\ \qquad = \sum_n \gamma\Big(\sqrt{n+1}|n+1\rangle + \sqrt{n}|n-1\rangle\Big) \langle n|x\rangle.
Suppose I attack this equation from the left with a particular \langle n&#039;|. Then I get
x\langle n&#039;|x\rangle = \sum_n \gamma\Big(\sqrt{n+1}\langle n&#039;|n+1\rangle + \sqrt{n}\langle n&#039;|n-1\rangle\Big) \langle n|x\rangle \\<br /> \qquad = \gamma\Big(\sqrt{n&#039;}\langle n&#039;-1|x\rangle + \sqrt{n&#039;+1}\langle n&#039;+1|x\rangle\Big),
which allows me to develop a recurrence relationship
C_{n+1} = \frac{x}{\gamma\sqrt{n+1}}C_n-\frac{\sqrt{n}}{\sqrt{n+1}}C_{n-1}.

But I don't understand what this says. What is that x doing in there? What does that even mean? And can I use this recurrence relation to get a closed-form answer? (At the very least I'd need to calculate C_0 and C_1 explicitly, which I don't know how to do.)

Also, I think at some point the position-space wavefunctions ought to come into it:
\langle x&#039;|n\rangle = \sqrt[4]{\frac{m\omega}{\pi\hbar}}\frac{1}{\sqrt{2^nn!}}H_n\Big(\sqrt{\frac{1}{\sqrt{2}\gamma} x}\Big)e^{-x^2/2\gamma^2}
and
\langle x&#039;|x\rangle = \delta(x-x&#039;).
 
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Hi.
\hat{x}=\gamma(\hat{a}†+ \hat{a})
Shows that you have to find common eigenstates of creation and annihilation operators. Are you familiar with quantum coherent states?
If not, you can find out by starting for example with:
|\alpha>=\sumcn|n>,
\hat{a}|\alpha>= \alpha|\alpha>
Get a recurrence relation for the coefficients and see if you obtain a familiar function at the end (hint: in terms of |0>). It might take a while but that's the right path...
 

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