Find the elements of the direct product

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SUMMARY

The discussion focuses on computing the direct sum of the groups Z_12 and U(10). Z_12 represents the integers modulo 12 under addition, while U(10) consists of the invertible elements {1, 3, 7, 9} under multiplication modulo 10. The direct sum combines these two groups, resulting in a set of ordered pairs representing all possible combinations of elements from Z_12 and U(10). The correct approach involves recognizing the structure of both groups and applying the direct sum operation accordingly.

PREREQUISITES
  • Understanding of group theory concepts, specifically direct sums.
  • Familiarity with modular arithmetic, particularly Z_n groups.
  • Knowledge of the group of units, U(n), and its properties.
  • Basic experience with ordered pairs and Cartesian products in set theory.
NEXT STEPS
  • Study the properties of direct sums in group theory.
  • Learn about the structure and elements of U(n) for various n.
  • Explore examples of direct sums involving different Z_n groups.
  • Investigate applications of modular arithmetic in cryptography and coding theory.
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Students of abstract algebra, mathematicians interested in group theory, and educators teaching modular arithmetic and group structures.

thetodd
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Homework Statement



Compute the direct sum Z_12 (+) U(10)

Z_24 is the group Z under addition modulo 12
U(10) is the group Z under multiplication modulo 10

The Attempt at a Solution


I have computed direct sums of Z_n groups before:

For example: Z_2 (+) Z_3 = {(0,0),(0,1),(0,2),(1,0),(1,1),(1,2)}

From this I would think I would follow a similar process but my textbook has the example:
U(8) (+) U(10) = {(1,1),(1,3),(1,7),(1,9),(3,1),(3,3),(3,7),(3,9),(5,1),(5,3),(5,7),(5,9),(7,1),(7,3),(7,7),(7,9)}

What's going on here?
 
Last edited:
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Maybe what you're missing is that U(10) is actually the group of invertibles in Z_10 under multiplication. Can you write down what the elements of U(10) are?
 
ok.. so U(10) = {1,3,7,9} under multiplication mod 10
and Z_12 = {0,1,2,3,4,5,6,7,8,9,10,11} under addition mod 12
 

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