Find the equation of the line of intersection of the planes:

Click For Summary
SUMMARY

The discussion focuses on finding the equation of the line of intersection of two planes defined by the equations 2x - y - z = 3 and x + 2y + 3z = 7. The solution involves calculating the cross product of the normal vectors of the planes, resulting in the direction vector <2, -1, -1> x <1, 2, 3>. Additionally, a point that satisfies both plane equations must be identified to fully represent the line of intersection.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with plane equations in three-dimensional space
  • Knowledge of solving systems of equations
  • Basic skills in linear algebra
NEXT STEPS
  • Study vector cross product calculations in detail
  • Learn how to derive equations of lines from parametric equations
  • Explore methods for solving systems of linear equations
  • Investigate applications of line intersections in three-dimensional geometry
USEFUL FOR

Students studying linear algebra, geometry enthusiasts, and anyone tackling problems involving the intersection of planes in three-dimensional space.

hargun519
Messages
2
Reaction score
0

Homework Statement



2x-y-z=3 and x+2y+3z=7

Homework Equations





The Attempt at a Solution



Im stumped on this problem because initially i thought all i had to do was make z, or another variable zero and then just solve. However, it then turns into a nasty problem. Most of the examples in my book, for one of the equations there are 2 variables instead of 3. Hence to make the substitution easier. So, my question is how would i start the problem then?

Any help will be appreciated
 
Physics news on Phys.org
There are two parts two a problem like this. First you'll want to find the direction of the line of intersection, which is nothing but the cross product of the normal vectors of the planes, i.e. \mathbf{n_1}\times\mathbf{n_2}=\langle 2,-1,-1\rangle \times \langle 1,2,3\rangle. Then all you need now to find the representation of the line is a point on that line right? So simply find an (x,y,z) value that satisfies both plane equations.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K