Find the first 3 terms of the asymptotic expansion of Jn(x)

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SUMMARY

The discussion focuses on deriving the first three terms of the asymptotic expansion of the Bessel function Jn(x) defined by the integral Jn(x) = (1/(inπ))∫0π e^(ixcosφ)cos(nφ)dφ, specifically when x equals n and n is a large positive integer. Participants clarify the justification for manipulating the integral and combining terms, emphasizing the transition from the integral limits of 0 to π to -π to π. The importance of recognizing the evenness of the cosine function in the exponential is highlighted as a key factor in the derivation process.

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Homework Statement


The bessel function Jn(x) is defined by the integral
Jn(x)=1/(inπ)∫0πeixcosφcos(nφ)dφ

From this formula, find the first 3 terms of the asymptotic expansion of Jn(x) when x=n and n is a large positive integer.

Homework Equations

The Attempt at a Solution


I tried combining the cos and exp term together
Jn(x) = ∫π ei(xcosφ+nφ)
 
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uaefame said:

Homework Statement


The bessel function Jn(x) is defined by the integral
Jn(x)=1/(inπ)∫0πeixcosφcos(nφ)dφ

From this formula, find the first 3 terms of the asymptotic expansion of Jn(x) when x=n and n is a large positive integer.

Homework Equations

The Attempt at a Solution


I tried combining the cos and exp term together
Jn(x) = ∫π ei(xcosφ+nφ)
How is this justified? ##e^{\cos(mx)} \cdot \cos(ny) \ne e^{\cos(mx + ny)}##.
 
Mark44 said:
How is this justified? ##e^{\cos(mx)} \cdot \cos(ny) \ne e^{\cos(mx + ny)}##.

Aside from the missing factor outside the integral, and a possible factor of 2 or 1/2, what he wrote is OK because he switched from ##\int_{\phi=0}^{\pi} \cdots## to ##\int_{\phi=-\pi}^{\pi} \cdots##, and used the evenness of the ##\cos(\phi)## in the exponential.
 

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