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First order term in the taylor expansion of ln(x) abut 1

  1. Aug 29, 2016 #1
    1. The problem statement, all variables and given/known data
    What's the first order term in the expansion ln(x) about x = 1?

    2. Relevant equations
    Taylor series formula

    3. The attempt at a solution
    The question is multiple choice, and the choices are x, 2x, or (1/2)x. However, when I calculate the first order term in the expansion of ln(x) about 1, I get ln(1) + (1/1)(x - 1) = x - 1, which is not one of the options. What am I doing wrong?
     
  2. jcsd
  3. Aug 29, 2016 #2

    SammyS

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    So, what's the first order term in x - 1 ?
     
  4. Aug 29, 2016 #3
    x... But how is that the answer if x - 1 is the first order term in the Taylor approximation?
     
  5. Aug 30, 2016 #4

    vela

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    Nothing. The problem statement is wrong or, at best, misleading. My guess is the intent was to ask what the linear term of ln(1+x) about x=0 is.
     
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