Find the length of the curve r = cos^2(theta/2)
I'm hopelessly lost.
consider a simpler case y=x^2 and what is the length from x=0 to x=10?
dlen = (dx*dx + dy*dy) ^ (1/2) based the pythagorian theorem
and dy= 2xdx
so dlen = ( dx*dx + 4x^2 dx*dx ) ^ (1/2) = (1 + 4x^2) dx
then integrate over x to get the solution
In your equation you must consider polar coordinates so that the dlen element is:
dlen = ( dr^2 + (r*dtheta)^2 ) ^ (1/2)
plugin for dr and r and integrate over theta to get the length
Thanks a lot, makes more sense! Forgive my ignorance by the way.
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