Find the magnetic field at the center

  • #1
306
13

Homework Statement


A wire carrying current I=7A is shaped as half circle of radius R=0.2m.The magnetic field B(in μT) at the center is :
A)11.0(k)
B)7.9(k)
C)9.4(k)
D)6.3(k)
E)4.0(-k)

Homework Equations


B=(μ0 I)/(2πR)

The Attempt at a Solution


B = (4π*10-7 *7)/(0.2*2*π) * 0.5 (Multiply by 1/2 because the wire is shaped as half circle).
B = 3.5*10-6 T = 3.5μT
Could anyone tell me where is my mistake?
 

Answers and Replies

  • #2
319
64
The formua for B that you used is for a straight wire. This wire is not straight.
 
  • #3
306
13
The formua for B that you used is for a straight wire. This wire is not straight.
B = (μ*I)/(4*π*r) *θ ?
 
  • #4
319
64
What is ##\theta## in your formula?
 
  • #5
306
13
What is ##\theta## in your formula?
B = (μ*I)/(2R) *0.5
= ( 4*10-7π *7)/(2*0.2) *0.5
= 10.99μT
=11 μT
 
Last edited:

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