The discussion centers on calculating the magnetic field at the origin due to three currents using the equation B = μ0 * I / (2π * r). The participants correctly compute the magnetic field contributions from each current, identifying the components for I1, I2, and I3. The final magnetic field components are determined to be Bx = -2.48 x 10^-5 T in the i direction and By = -4.66 x 10^-5 T in the j direction. Participants emphasize the importance of correctly applying the right-hand rule and maintaining proper signs for vector components.
PREREQUISITESStudents studying electromagnetism, physics educators, and anyone involved in electrical engineering or related fields seeking to deepen their understanding of magnetic fields and vector analysis.
Yes, that was the mistake. So, your final answer is?gkamal said:actually the -4.66x10^-5 is negative not positive i just edited it like 2 sec b4 ur reply i hope this was the mistake
That's not how I think about it. The field ##\vec{B}_3## produced by ##I_3## is a vector. So, I would not refer to it as being positive or negative. It has a magnitude that is positive. (All vectors have positive magnitude, by definition.) However, when I draw the direction of ##\vec{B}_3## in a sketch using the right hand rule for magnetic fields, I can see that it points to the right. So, the x-component is positive. [Edited]gkamal said:Yes it is right but just to make sure the B of I3 becomes positive because it's value is negative and it is point in the -x , thus it would be point in the +x with a positive value since 2 negatives cancel right?
You are welcome. Glad I could be of some help.btw thank you so much for your help