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Find the magnitude and the direction of the electric field at the thir

  1. Sep 10, 2013 #1
    1. The problem statement, all variables and given/known data
    Two point charges are placed at two of the corners of a triangle as shown in the figure. (Take q1 = -11.3 μC, and q2 = 15.4 μC.) Find the magnitude and the direction of the electric field at the third corner of the triangle. {Correct Answer: 1.07e+07 N/C at 71.2 degrees above the -x-axis}


    2. Relevant equations
    F = ((1)/(4πε0))(q1*q2/r^2)

    3. The attempt at a solution
    Attached files. What am i doing wrong? I can't seem to get the correct answer.
     

    Attached Files:

    Last edited: Sep 10, 2013
  2. jcsd
  3. Sep 10, 2013 #2

    TSny

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    Did you convert units correctly? Your answers appear to be off by some factors of 10.

    Is Ey from q1 positive or negative? [Edited]
     
  4. Sep 10, 2013 #3
    Hmm I don't know how I got a negative. But either way when I solve for the magnitude it'll end up being positive. Which unit should I convert? The μc or cm?
     
  5. Sep 10, 2013 #4

    TSny

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    Yes, but the sign of Ey will affect the answer for the direction angle.
    Neither μC nor cm is an SI unit.
     
  6. Sep 10, 2013 #5
    Thanks, turns out it was just my conversion.
     
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