Find the mass of a piece of a cylinder

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Homework Help Overview

The problem involves finding the mass of a piece of a cylinder defined by the equation x^2 + y^2 = 1, situated in the first octant, above the plane z=0 and below the plane z=1-x, with a density function D=x. Participants are exploring the implications of calculating mass for a solid versus a surface integral.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • One participant initially set up a triple integral to calculate the mass but later realized the need for a surface integral. Another participant questioned the nature of the mass of a surface, expressing confusion about how a surface could possess mass.

Discussion Status

The discussion has evolved with participants exploring the distinction between solid and surface mass calculations. Some guidance has been offered regarding the interpretation of the problem, and there is acknowledgment of the confusion surrounding the mass of surfaces.

Contextual Notes

Participants noted that the problem was taken from an old quiz, and there is a concern about the counterintuitive nature of calculating mass for a surface, which raises questions about assumptions in the problem statement.

Feodalherren
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Homework Statement


Find the mass of the piece of a cylinder x^2 + y^2 =1 that lies in the first octant above z=0 and below z=1-x.
The density is D=x.

Homework Equations


The Attempt at a Solution


I set up this integral:

\int^{\pi/2}_{0} \int^{1}_{0} \int^{1-rcos\theta}_{0} r^{2}cos\theta dz dr d\theta

Which ends up coming out as \frac{1}{3} - \frac{\pi}{16}

The correct answer is 1- \frac{\pi}{4}
 
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Nevermind I figured it out. They only wanted the "shell" mass. I had to do a surface integral.
 
Feodalherren said:

Homework Statement


Find the mass of the piece of a cylinder x^2 + y^2 =1 that lies in the first octant above z=0 and below z=1-x.
The density is D=x.

Homework Equations


The Attempt at a Solution


I set up this integral:

\int^{\pi/2}_{0} \int^{1}_{0} \int^{1-rcos\theta}_{0} r^{2}cos\theta dz dr d\theta

Which ends up coming out as \frac{1}{3} - \frac{\pi}{16}

The correct answer is 1- \frac{\pi}{4}

Do you recall the discussion in your previous post about the mass of a funnel? There was confusion whether your problem was to give the mass of a solid or a surface. You have the same issue in this problem. You have worked it as the mass of a solid piece of a cylinder in the first octant under that plane. Are you sure you aren't supposed to be thinking of a thin metal sheet forming just the curved surface of that cylinder? In that case you would want a surface integral. It would help if you would state the problem completely and exactly as it appears in your book. My guess it that it is supposed to be a surface integral.

[Edit] I see you figured it out while I was typing my response.
 
This question actually came off an old quiz and it was stated on it exactly as I typed it. It seems counter intuitive to me anyway. Isn't the surface just infinitely thin and thus without mass? This whole idea seems weird to me. How could a surface possibly have mass?
 
It can be a useful approximation for some physical situations when one dimension is negligible in comparison to the other two.
 
How do you mean? Could you give me an example of a physical interpretation? One that's applicable to engineering would be awesome :).
 
Things that are thin, like a sheet of paper, a steel plate, gold foil, etc.
 
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Hmm yeah ok fair enough. Thanks.
 

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