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## Homework Statement

A rocket is accelerating upward at 3.70 m/s^2 from the launchpad on the earth. Inside a small 1.50-Kg ball hangs from the ceiling by a light 1.10m wire.

a)If the ball is displaced 8.50 degrees from the vertical and released, find the amplitude of the resulting swings of this pendulum

b)If the ball is displaced 8.50 degrees from the vertical and released, find the period of the resulting swings of this pendulum

## Homework Equations

x=A(coswt+θ)

-mgθ=-mgx/L

θL=x

w=sqrt(g/L)

T=2pi sqrt(g/L)

## The Attempt at a Solution

okay first we convert θ into radians whihc is 0.1484 rads

the new g' of the rocket is g-a

_{rocket}=9.8-3.7=6.1 m/s^2

θL=x 0.1484*1.1=0.16324m

w=sqrt(g/L)=sqrt(6.1/1.1)=2.3549

x=A(coswt+θ)

A=x/cos(wt+θ) now taking t for 0 (this is probably the part where I made my mistake)

A=0.16324/cos(0+0.1484)=0.1148 for the amplitude

b)

T=2pi sqrt(g/L)

T=2pi sqrt(6.1/1.1)=2.67s

In both cases my answers are wrong, if anyone could give me a pointer I would appreciate the help.