Find the principal stresses in a shaft with torque applied

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SUMMARY

This discussion focuses on calculating principal stresses in a shaft subjected to torque. The participant calculated the polar moment of inertia (J) as 38.35e-9 m4 and the area moment of inertia (I) as 19.17e-9 m4. Using these values, they derived a normal stress (σ) of 82.16 MPa and a shear stress (τ) of 41.07 MPa. The maximum principal stress (σmax) was determined to be 99.17 MPa, while the minimum principal stress (σmin) was -17.01 MPa, leading to confusion regarding the calculation of alternating (σa) and mean stresses (σm) and the appropriate factor of safety (FoS).

PREREQUISITES
  • Understanding of shear and normal stress equations
  • Familiarity with Mohr's Circle for stress analysis
  • Knowledge of polar and area moments of inertia
  • Concept of factor of safety in mechanical design
NEXT STEPS
  • Learn how to calculate the factor of safety using the Soderberg criterion
  • Study the application of Mohr's Circle in complex stress states
  • Research the effects of bending stress in torsional loading scenarios
  • Explore advanced topics in fatigue analysis for rotating shafts
USEFUL FOR

Mechanical engineers, students studying mechanics of materials, and professionals involved in stress analysis and design of rotating machinery will benefit from this discussion.

Kyle Grayston
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Homework Statement


8tgqJGX.jpg


Homework Equations


M = Fd
σ/y = M/I
T/J = τ/r
σalternating (σa) = σmax - σmin / 2
σmean (σm) = σmax + σmin / 2
soderberg: σa/σ'e + σm/σy = 1/FoS

The Attempt at a Solution


I am still unsure whether my progress so far is correct but..
I have calculated J to be 38.35e-9 m4 and I to be 19.17e-9 m4. I then use these values in the shear stress and normal stress equations to find that:

σ = 82.16 MPa
τ = 41.07 MPa

I apply these values to a loading element diagram (am I right in thinking there is no force in the y direction??) and then used Mohrs circle to find that the maximum and minimum principal stresses are:

σmax = 99.17 MPa
σmin = -17.01 MPa

When applying these values to the σalternating and σmean equations, I am not sure whether it is expressed as:

σa = σmax - σmin / 2
σa = 99.17 - (-17.01) / 2 OR
σa = 99.17 - 17.01 / 2

After I get the correct σa and σm values and I need to find a suitable factor of safety, I'll have σa, σm, σy but I am not sure how I am to find the σ'e, or is there a different method to finding a suitable factor of safety?
 

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I'm not sure whether they really intended for you to be considering the bending of the shaft in addition to the torque. What do you think?
 
Chestermiller said:
I'm not sure whether they really intended for you to be considering the bending of the shaft in addition to the torque. What do you think?

I see what you're saying, I guess when I saw 'principal stresses' I thought about what we had learned in class and to draw mohrs circle. I am not sure how I would go about finding the maximum and minimum principal stresses without applying a bending stress? I have drawn the following loading element:

gNiNW9p.jpg


Im just unsure as to whether I am on the right track with this..
 

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