1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Radial Deflection of a rotating shaft

  1. Sep 3, 2015 #1

    billy_joule

    User Avatar
    Science Advisor

    This is a series of question that appear to become more and more vague, the last part has me stumped.

    1. The problem statement, all variables and given/known data

    A) I have an electric motor that produces 0.4 HP of shaft power at a speed of 2800rpm. What will the gearbox speed and torque be on the output of a 1:5 (in : out) gearbox? Assume a 96% efficient gearbox

    B) design a shaft that is 100mm long to transmit the gearbox output torque of the above problem using sensible engineering assumptions. Select a material and design the diameter.

    C) assume that you have a centrifugal pump impeller at the end of the shaft you designed in the above problem. What will be the maximum radial deflection at the tip of the centrifugal impeller with respect to the shaft? Assume that the impeller is rigid (does not deflect) and has a diameter of 100mm. Assume all deflection is from the 100mm long shaft only.


    3. The attempt at a solution


    Question A) is straight forward:
    Poutput = Pin *η = 0.4HP * 0.96 = 0.384 HP

    Rpmout = Rpm in * 5/1 = 14,000 RPM

    HP = RPM* T / 5252

    Tout = HPout*5252/RPM
    = 0.386HP *5252 / 14,000 RPM = 0.1448 ft lb


    For Question B), I think the simplest interpretation is "how thick must a solid shaft be to resist 0.1448 ft lb of torsion?"
    I choose 316 SS (SS because it's for a pump, 316 because it's common) with yield stress of 205 MPa and a safety factor of 3.
    So
    0.1448 ft lb = 0.1963 Nm

    τmax = 205 MPa/3 = 68.3 MPa


    d55d8906a31aceb09920397449d992b2.png


    = (16x 0.1963 Nm / (π * 68.3 MPa) )1/3

    = 2.446 mm

    Which is expectedly thin, and such a slender shaft would likely undergo whirling before 14,000rpm.

    Would the next step be to find the minimum diameter that gives a critical speed beyond 14,000rpm?
    That would require some assumptions about how it's supported, simply supported at both ends would be the obvious assumption.

    Part C) has me stumped:

    I would think the only radial stress would be due to the centrifugal force on the self weight of the shaft (and the blade weight if I estimated and included it).

    Is it really asking me find the increase in radius of the shaft due to the speed of rotation?

    I've only ever seen radial deflection in the context of pressure vessels & piping. I understand blade tip clearance is important but I'd assume the radial deflection of the shaft is inconsequential compared to the that of the blades themselves. Or is there some other interpretation?
     
  2. jcsd
  3. Sep 3, 2015 #2

    Nidum

    User Avatar
    Science Advisor
    Gold Member

    The final question is practically gibberish . Even if we could put a meaningful interpretation on it there is still not enough data to get an answer .

    The only thing that somewhat makes sense is that questioner is suggesting that CF pump is a crude single outlet type which discharges water tangentially to rotor . In that case rotor sees a torque and a radial load .
     
  4. Sep 3, 2015 #3
    No, I think it is asking what force the fluid will exert upon the shaft.

    This gives some idea of what it is all about.
    http://www.mcnallyinstitute.com/06-html/6-5.html
     
  5. Sep 3, 2015 #4

    billy_joule

    User Avatar
    Science Advisor

    Thanks, that's what I thought. The problem is, this is a part of a 'take home test' for a graduate engineering role I interviewed for at a prestigious aerospace company, so it's particularly high stakes homework for me. At this point, I think It'll be better to skip it rather than plough through and get some result based on a string on assumptions.


    It seems the radial force (if any) depends on where on the pump curve the pump is operating, something I have absolutely no info on. I'd also need info on the geometry of the shaft support at the pump.

     
  6. Sep 3, 2015 #5

    Nidum

    User Avatar
    Science Advisor
    Gold Member

    I know it says radial deflection but it could be loosely interpreted as torsion wise deflection - ie shaft twist . You have enough information to work that out properly .

    In any case working out twist of a tentative shaft design to see if it is within safe limits would be a good thing to do .

    Since your first shaft comes out at such small diameter you may like to choose a more generous size based on ' engineering judgement ' and give an explanation of reasons in your answer .

    You could also give a descriptive account of concerns about whirling and hydraulic and mechanical unbalance .
     
    Last edited: Sep 3, 2015
  7. Sep 3, 2015 #6
    Not all impellers are enclosed within a housing.

    I gave you the reference so as to give you the ability to reflect upon on how a radial deflection can occur.

    There are many tools and industrial applications where it would be desirable to know the deflection and forces on a shaft. Circular sanders, drill bits, agitators, are just a few examples where the working part of the tool is supported only on one end. The defection can be caused by the production of pressure difference across the tool end, by encountering different properties of the working material, by movement of the tool itself.

    In that instance yes. You also have no information on the working fluid. It could be viscous such as concrete mixture, or a more freely flowing such as water. The article does though give you the fact that if optimally operating the shaft "should" experience no deviance from perfect rotation. The problem also does not give you the mass of the impeller and related to determine dynamics and harmonics.


    Sorry, but that is a cop out. Engineering is based on assumptions that try to model the real world on what facts are available.
    The prestigious aerospace company may decide one day to enter into a design of a drill to be part of an endeavor for asteroid mining, and need to ensure that their drill, when sent up to the asteroid does its job. You are asked by your supervisor.to determine the maximum deflection of the drill bit.

    You have one piece of given information with which you can determine a deflection. That is the torque.
     
  8. Sep 3, 2015 #7

    billy_joule

    User Avatar
    Science Advisor

    I ended up calculating the arc length the impeller tip traverses due to the shaft twist and justified why I did so rather than try to find a radial deflection.
    I also checked if the shaft was at risk of whirling, it wasn't.
    I appreciate the responses, good advice.
     
  9. Sep 3, 2015 #8
    Shaft twist is not radial deflection. That is not what is asked, no matter what explanation give.

    Why have you not considered the simple answer with what happens if a blade tip binds against a surface and stops turning?
     
  10. Sep 4, 2015 #9

    billy_joule

    User Avatar
    Science Advisor

    Short of a foreign object entering the pump, isn't radial deflection a prerequisite for binding?
    And if binding did occur, wouldn't it be a constraint on radial deflection?
     
    Last edited: Sep 4, 2015
  11. Sep 4, 2015 #10

    Nidum

    User Avatar
    Science Advisor
    Gold Member

    You could do a limit state case where the impeller is assumed to be reacting all the pumping load on one side only and at maximum radius . No explanation need be given except that this is worst possible case . Radial load on shaft is then determinate and beam wise deflection of shaft can be worked out .

    It did occur to me overnight that question part 3 might be an initiative test . Engineering problems often have to be solved where there is insufficient data and questioner might just be seeing what you make of a partially defined problem .

    More generally the concept of limit state analysis of structural problems or indeed many other problems is a very powerful tool though little used and seldom taught .
     
  12. Sep 4, 2015 #11
    I would tend to agree.
    If parts A and B would be worth 10 points each, Part C in relation would be 80 points.
     
  13. Sep 4, 2015 #12
    Kind of a catch 22 isn't it.

    I'll try to get back as soon as possible
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Radial Deflection of a rotating shaft
  1. Hollow shaft rotation (Replies: 3)

Loading...